1.  Niharika borrows Rs.10000 for 2 years at 4% p.a. Simple interest. She immediately lends money to Girish at 50/4% p.a. for 2 years. Find the gain of 1 year?

Rs.700
Rs.650
Rs.850
Rs.800

```Answer

Answer: Option  C Explanation:Explanation :(10000*50*1/ 4*100 ) –  (10000*4*1 / 100)
1250-400 = 850 ```

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2.  A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is:

Rs. 720
Rs. 698
Rs. 678
D) Rs. 696

```Answer

Answer: Option  B Explanation:S.I. for 1 year = Rs. (854 - 815) = Rs. 39.
S.I. for 3 years = Rs.(39 x 3) = Rs. 117.
Principal = Rs. (815 - 117) = Rs. 698. ```

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3.  A person borrows Rs. 5000 for 2 years at 4% p.a. simple interest. He immediately lends it to another person at 6.25% p.a. for 2 years.Find his gain in the transaction per year.

Rs. 112.50
Rs. 175
Rs. 150
Rs. 125.50

```Answer

Answer: Option  A Explanation:Gain in 2 years = Rs. [{(5000×6.25×2)/100} – {(5000×4×2)/100}]
= Rs. (625- 400) = Rs. 225.
So gain in 1 year = Rs.225/ 2 = Rs. 112.50 ```

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4.  A sum fetched a total simple interest of Rs. 4016.25 at the rate of 9 % p.a. in 5 years. What is the sum?

Rs. 8045
Rs. 8925
Rs. 8900
Rs. 8032.45

```Answer

Answer: Option  B Explanation:Sum = (100× S.I.)/ r × t
= (100 × 4016.25)/ 9 × 5 = Rs. 8925  ```

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5.  The simple interest on a sum of money will be rupees 400 after 5 years. In the next 5 years the principal is doubled, what will be the total interest at the end of the 10th year

800
1000
1200
1600

```Answer

Answer: Option  C Explanation:400 = p*(r/100)*5, pr = 8000
SI = 2p*(r/100)*5 = pr/10 = 8000/10 = 800
Total interest = 400 + 800 = 1200 ```

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