1.  Find the CI on Rs.4500 at 4% pa for 2 yrs compounded half yearly(approx) ?

963
369
370
675

```Answer

Answer: Option  B Explanation:CI = P [(1+(r/100)n – 1] = 4500[(1+2/100)4 – 1
= 4500[ (102*102*102*102/100*100*100*100) – 1] = 4500[1.082 – 1] = 4500*0.082 = 369 ```

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2.  Aswin invested an amount of Rs.9000 in a fixed deposit scheme for 2 years at CI rate 6% pa. How much amount will Aswin get on maturity of the fixed amount ?

9500
9800
10112
7000

```Answer

Answer: Option  C Explanation:Amount = 9000*106/100*106/100
= 9000*53/50*53/50
= 10,112 ```

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3.  The difference between the total simple interest and the total compound interest compounded annually at the same rate of interest on a sum of money at the end of two years is Rs. 350. What is definitely the rate of interest per cent per annum?

9400
7000
6300

```Answer

Answer: Option  D Explanation:Difference = Pr2/(100)2
= (350×100×100)/(P×r2)
P is not given ```

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4.  Rohit borrowed Rs. 1200 at 12% PA .He repaid Rs. 500 at the end of 1 year. What is the amount required to pay at the end of 2nd year to discharge his loan which was calculated in CI

900
945
945.28
950

```Answer

Answer: Option  C Explanation:CI at the end of 1st year = 1200 *( 1+(12 /100)) = 1344
CI= 1344-1200 = 144
500 paid then remaining amount = 1344 – 500 = 844
At the end of  2nd year
844*[(1+(12/100)] =945.28 ```

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5.  What is the difference between the CI and SI on Rs.6500 at the rate of 4 pc pa in 2 yrs ?

9.4
10.4
15.4
14.5

```Answer

Answer: Option  B Explanation:SI = 6500*4*2/100 = 520
CI = 6500*(104/100)*(104/100) = 7030.4 = 530.4
530.4 – 520 = 10.4 ```

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