1.  The cost of cultivating a square field at the rate of Rs. 135 per hectare is Rs. 1215. The cost of putting a fence around it at the rate of 75 paise per metre would be :


Rs. 360
Rs. 810
Rs. 900
Rs. 1800


Answer

 Option

Area = Total costRate = 1215135 hectares = (9 * 10000) sq. m. Side of the square =90000 = 300 m. Perimeter of the field = (300 * 4) - 1200 m. Cost of fencing = Rs. (1200 * 34) = Rs. 900.

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2.  A room is 15 feet long and 12 feet broad. A mat has to be placed on the floor of this room leaving 112 feet from the walls. What will be the cost of the mat at the rate of Rs. 3.50 per square feet ?


Rs. 378
Rs. 472.50
Rs. 496
Rs. 630


Answer

 Option

Area of the mat = [(15 - 3) * (12 - 3)] sq. ft = 108 sq. ft. Cost of the mat = Rs. (108 * 3.50) = Rs. 378.

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3.  What will be the cost of gardening 1 metre broad boundary around a rectangular plot having perimeter of 340 metres at the rate of Rs. 10 per square metre ?


Rs. 1700
Rs. 3400
Rs. 3440
Cannot be determined


Answer

 Option

2(l + b) = 340 (Given). Area of the boundary = [(l + 2) (b + 2) - lb] = 2(l + b) + 4 = 344. Cost of gardening = Rs. (344 * 10) = Rs. 3440.

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4.  A rectangular lawn 55 m by 35 m has two roads each 4 m wide running in the middle of it, one parallel to length and the other parallel to breadth. The cost of gravelling the roads at 75 paise per sq. metre is :


Rs. 254.50
Rs. 258
Rs. 262.50
Rs. 270


Answer

 Option

Area of crossroads = (55 * 4 + 35 * 4 - 4 * 4)m2 = 344 m2. Cost of gravelling = Rs. (344 * 75100) = Rs. 258.

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5.  A square and a rectangle have equal areas. If their perimeters are p1 and p2 respectively, then :


p1 < p2
p1 = p2
p1 > p2
None of the above


Answer

 Option

A square and a rectangle with equal areas will satisfy the relation p1 < p2.

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