1. The cost of cultivating a square field at the rate of Rs. 135 per hectare is Rs. 1215. The cost of putting a fence around it at the rate of 75 paise per metre would be :

A. Rs. 360 B. Rs. 810 C. Rs. 900 D. Rs. 1800

Answer Answer: Option C Explanation: Area = ^{Total cost}⁄_{Rate} = ^{1215}⁄_{135} hectares = (9 * 10000) sq. m.
Side of the square =$\sqrt{\mathrm{90000}}$ = 300 m.
Perimeter of the field = (300 * 4) - 1200 m.
Cost of fencing = Rs. (1200 * ^{3}⁄_{4}) = Rs. 900.

2. A room is 15 feet long and 12 feet broad. A mat has to be placed on the floor of this room leaving 1^{1}⁄_{2} feet from the walls. What will be the cost of the mat at the rate of Rs. 3.50 per square feet ?

A. Rs. 378 B. Rs. 472.50 C. Rs. 496 D. Rs. 630

Answer Answer: Option A Explanation: Area of the mat = [(15 - 3) * (12 - 3)] sq. ft = 108 sq. ft.
Cost of the mat = Rs. (108 * 3.50) = Rs. 378.

3. What will be the cost of gardening 1 metre broad boundary around a rectangular plot having perimeter of 340 metres at the rate of Rs. 10 per square metre ?

A. Rs. 1700 B. Rs. 3400 C. Rs. 3440 D. Cannot be determined

Answer Answer: Option C Explanation: 2(l + b) = 340 (Given).
Area of the boundary = [(l + 2) (b + 2) - lb] = 2(l + b) + 4 = 344.
Cost of gardening = Rs. (344 * 10) = Rs. 3440.

4. A rectangular lawn 55 m by 35 m has two roads each 4 m wide running in the middle of it, one parallel to length and the other parallel to breadth. The cost of gravelling the roads at 75 paise per sq. metre is :

A. Rs. 254.50 B. Rs. 258 C. Rs. 262.50 D. Rs. 270

Answer Answer: Option B Explanation: Area of crossroads = (55 * 4 + 35 * 4 - 4 * 4)m^{2} = 344 m^{2}.
Cost of gravelling = Rs. (344 * ^{75}⁄_{100}) = Rs. 258.